=================================================================== RCS file: /cvs/mandoc/Attic/apropos_db.c,v retrieving revision 1.4 retrieving revision 1.5 diff -u -p -r1.4 -r1.5 --- mandoc/Attic/apropos_db.c 2011/11/14 10:07:06 1.4 +++ mandoc/Attic/apropos_db.c 2011/11/18 07:02:19 1.5 @@ -1,4 +1,4 @@ -/* $Id: apropos_db.c,v 1.4 2011/11/14 10:07:06 kristaps Exp $ */ +/* $Id: apropos_db.c,v 1.5 2011/11/18 07:02:19 kristaps Exp $ */ /* * Copyright (c) 2011 Kristaps Dzonsons * Copyright (c) 2011 Ingo Schwarze @@ -32,11 +32,30 @@ #include "apropos_db.h" #include "mandoc.h" +struct rec { + struct res res; /* resulting record info */ + /* + * Maintain a binary tree for checking the uniqueness of `rec' + * when adding elements to the results array. + * Since the results array is dynamic, use offset in the array + * instead of a pointer to the structure. + */ + int lhs; + int rhs; + int matched; /* expression is true */ + int *matches; /* partial truth evaluations */ +}; + struct expr { - int regex; - int mask; - char *v; - regex_t re; + int regex; /* is regex? */ + int index; /* index in match array */ + int mask; /* type-mask */ + int cs; /* is case-sensitive? */ + int and; /* is rhs of logical AND? */ + char *v; /* search value */ + regex_t re; /* compiled re, if regex */ + struct expr *next; /* next in sequence */ + struct expr *subexpr; }; struct type { @@ -64,14 +83,22 @@ static const struct type types[] = { }; static DB *btree_open(void); -static int btree_read(const DBT *, const struct mchars *, char **); -static int exprexec(const struct expr *, char *, int); +static int btree_read(const DBT *, + const struct mchars *, char **); +static int expreval(const struct expr *, int *); +static void exprexec(const struct expr *, + const char *, int, struct rec *); +static int exprmark(const struct expr *, + const char *, int, int *); +static struct expr *exprexpr(int, char *[], int *, int *, size_t *); +static struct expr *exprterm(char *, int); static DB *index_open(void); static int index_read(const DBT *, const DBT *, const struct mchars *, struct rec *); static void norm_string(const char *, const struct mchars *, char **); static size_t norm_utf8(unsigned int, char[7]); +static void recfree(struct rec *); /* * Open the keyword mandoc-db database. @@ -300,13 +327,13 @@ index_read(const DBT *key, const DBT *val, left = val->size; cp = (char *)val->data; - rec->rec = *(recno_t *)key->data; + rec->res.rec = *(recno_t *)key->data; - INDEX_BREAD(rec->file); - INDEX_BREAD(rec->cat); - INDEX_BREAD(rec->title); - INDEX_BREAD(rec->arch); - INDEX_BREAD(rec->desc); + INDEX_BREAD(rec->res.file); + INDEX_BREAD(rec->res.cat); + INDEX_BREAD(rec->res.title); + INDEX_BREAD(rec->res.arch); + INDEX_BREAD(rec->res.desc); return(1); } @@ -314,38 +341,37 @@ index_read(const DBT *key, const DBT *val, * Search the mandocdb database for the expression "expr". * Filter out by "opts". * Call "res" with the results, which may be zero. + * Return 0 if there was a database error, else return 1. */ -void +int apropos_search(const struct opts *opts, const struct expr *expr, - void *arg, void (*res)(struct rec *, size_t, void *)) + size_t terms, void *arg, + void (*res)(struct res *, size_t, void *)) { - int i, len, root, leaf; + int i, rsz, root, leaf, mask, mlen, rc, ch; DBT key, val; DB *btree, *idx; struct mchars *mc; - int ch; char *buf; recno_t rec; - struct rec *recs; - struct rec srec; + struct rec *rs; + struct res *ress; + struct rec r; + rc = 0; root = -1; leaf = -1; btree = NULL; idx = NULL; mc = NULL; buf = NULL; - recs = NULL; - len = 0; + rs = NULL; + rsz = 0; - memset(&srec, 0, sizeof(struct rec)); + memset(&r, 0, sizeof(struct rec)); - /* XXX: error out with bad regexp? */ - mc = mchars_alloc(); - /* XXX: return fact that we've errored? */ - if (NULL == (btree = btree_open())) goto out; if (NULL == (idx = index_open())) @@ -362,7 +388,13 @@ apropos_search(const struct opts *opts, const struct e if ( ! btree_read(&key, mc, &buf)) break; - if ( ! exprexec(expr, buf, *(int *)val.data)) + mask = *(int *)val.data; + + /* + * See if this keyword record matches any of the + * expressions we have stored. + */ + if ( ! exprmark(expr, buf, mask, NULL)) continue; memcpy(&rec, val.data + 4, sizeof(recno_t)); @@ -374,19 +406,31 @@ apropos_search(const struct opts *opts, const struct e */ for (leaf = root; leaf >= 0; ) - if (rec > recs[leaf].rec && recs[leaf].rhs >= 0) - leaf = recs[leaf].rhs; - else if (rec < recs[leaf].rec && recs[leaf].lhs >= 0) - leaf = recs[leaf].lhs; + if (rec > rs[leaf].res.rec && + rs[leaf].rhs >= 0) + leaf = rs[leaf].rhs; + else if (rec < rs[leaf].res.rec && + rs[leaf].lhs >= 0) + leaf = rs[leaf].lhs; else break; - if (leaf >= 0 && recs[leaf].rec == rec) + /* + * If we find a record, see if it has already evaluated + * to true. If it has, great, just keep going. If not, + * try to evaluate it now and continue anyway. + */ + + if (leaf >= 0 && rs[leaf].res.rec == rec) { + if (0 == rs[leaf].matched) + exprexec(expr, buf, mask, &rs[leaf]); continue; + } /* - * Now we actually extract the manpage's metadata from - * the index database. + * We have a new file to examine. + * Extract the manpage's metadata from the index + * database, then begin partial evaluation. */ key.data = &rec; @@ -395,52 +439,62 @@ apropos_search(const struct opts *opts, const struct e if (0 != (*idx->get)(idx, &key, &val, 0)) break; - srec.lhs = srec.rhs = -1; - if ( ! index_read(&key, &val, mc, &srec)) + r.lhs = r.rhs = -1; + if ( ! index_read(&key, &val, mc, &r)) break; - if (opts->cat && strcasecmp(opts->cat, srec.cat)) + /* XXX: this should be elsewhere, I guess? */ + + if (opts->cat && strcasecmp(opts->cat, r.res.cat)) continue; - if (opts->arch && strcasecmp(opts->arch, srec.arch)) + if (opts->arch && strcasecmp(opts->arch, r.res.arch)) continue; - recs = mandoc_realloc - (recs, (len + 1) * sizeof(struct rec)); + rs = mandoc_realloc + (rs, (rsz + 1) * sizeof(struct rec)); - memcpy(&recs[len], &srec, sizeof(struct rec)); + memcpy(&rs[rsz], &r, sizeof(struct rec)); + rs[rsz].matches = mandoc_calloc(terms, sizeof(int)); + exprexec(expr, buf, mask, &rs[rsz]); /* Append to our tree. */ if (leaf >= 0) { - if (rec > recs[leaf].rec) - recs[leaf].rhs = len; + if (rec > rs[leaf].res.rec) + rs[leaf].rhs = rsz; else - recs[leaf].lhs = len; + rs[leaf].lhs = rsz; } else - root = len; + root = rsz; - memset(&srec, 0, sizeof(struct rec)); - len++; + memset(&r, 0, sizeof(struct rec)); + rsz++; } + + /* + * If we haven't encountered any database errors, then construct + * an array of results and push them to the caller. + */ - if (1 == ch) - (*res)(recs, len, arg); + if (1 == ch) { + for (mlen = i = 0; i < rsz; i++) + if (rs[i].matched) + mlen++; + ress = mandoc_malloc(mlen * sizeof(struct res)); + for (mlen = i = 0; i < rsz; i++) + if (rs[i].matched) + memcpy(&ress[mlen++], &rs[i].res, + sizeof(struct res)); + (*res)(ress, mlen, arg); + free(ress); + rc = 1; + } - /* XXX: else? corrupt database error? */ out: - for (i = 0; i < len; i++) { - free(recs[i].file); - free(recs[i].cat); - free(recs[i].title); - free(recs[i].arch); - free(recs[i].desc); - } + for (i = 0; i < rsz; i++) + recfree(&rs[i]); - free(srec.file); - free(srec.cat); - free(srec.title); - free(srec.arch); - free(srec.desc); + recfree(&r); if (mc) mchars_free(mc); @@ -450,24 +504,149 @@ out: (*idx->close)(idx); free(buf); - free(recs); + free(rs); + return(rc); } +static void +recfree(struct rec *rec) +{ + + free(rec->res.file); + free(rec->res.cat); + free(rec->res.title); + free(rec->res.arch); + free(rec->res.desc); + + free(rec->matches); +} + struct expr * -exprcomp(char *buf) +exprcomp(int argc, char *argv[], size_t *tt) { - struct expr *p; + int pos, lvl; + struct expr *e; + + pos = lvl = 0; + *tt = 0; + + e = exprexpr(argc, argv, &pos, &lvl, tt); + + if (0 == lvl && pos >= argc) + return(e); + + exprfree(e); + return(NULL); +} + +/* + * Compile an array of tokens into an expression. + * An informal expression grammar is defined in apropos(1). + * Return NULL if we fail doing so. All memory will be cleaned up. + * Return the root of the expression sequence if alright. + */ +static struct expr * +exprexpr(int argc, char *argv[], int *pos, int *lvl, size_t *tt) +{ + struct expr *e, *first, *next; + int log; + + first = next = NULL; + + for ( ; *pos < argc; (*pos)++) { + e = next; + + /* + * Close out a subexpression. + */ + + if (NULL != e && 0 == strcmp(")", argv[*pos])) { + if (--(*lvl) < 0) + goto err; + break; + } + + /* + * Small note: if we're just starting, don't let "-a" + * and "-o" be considered logical operators: they're + * just tokens unless pairwise joining, in which case we + * record their existence (or assume "OR"). + */ + log = 0; + + if (NULL != e && 0 == strcmp("-a", argv[*pos])) + log = 1; + else if (NULL != e && 0 == strcmp("-o", argv[*pos])) + log = 2; + + if (log > 0 && ++(*pos) >= argc) + goto err; + + /* + * Now we parse the term part. This can begin with + * "-i", in which case the expression is case + * insensitive. + */ + + if (0 == strcmp("(", argv[*pos])) { + ++(*pos); + ++(*lvl); + next = mandoc_calloc(1, sizeof(struct expr)); + next->cs = 1; + next->subexpr = exprexpr(argc, argv, pos, lvl, tt); + if (NULL == next->subexpr) { + free(next); + next = NULL; + } + } else if (0 == strcmp("-i", argv[*pos])) { + if (++(*pos) >= argc) + goto err; + next = exprterm(argv[*pos], 0); + } else + next = exprterm(argv[*pos], 1); + + if (NULL == next) + goto err; + + next->and = log == 1; + next->index = (int)(*tt)++; + + /* Append to our chain of expressions. */ + + if (NULL == first) { + assert(NULL == e); + first = next; + } else { + assert(NULL != e); + e->next = next; + } + } + + return(first); +err: + exprfree(first); + return(NULL); +} + +/* + * Parse a terminal expression with the grammar as defined in + * apropos(1). + * Return NULL if we fail the parse. + */ +static struct expr * +exprterm(char *buf, int cs) +{ struct expr e; + struct expr *p; char *key; - int i, icase; + int i; - if ('\0' == *buf) - return(NULL); + memset(&e, 0, sizeof(struct expr)); - /* - * Choose regex or substring match. - */ + e.cs = cs; + /* Choose regex or substring match. */ + if (NULL == (e.v = strpbrk(buf, "=~"))) { e.regex = 0; e.v = buf; @@ -476,18 +655,11 @@ exprcomp(char *buf) *e.v++ = '\0'; } - /* - * Determine the record types to search for. - */ + /* Determine the record types to search for. */ - icase = 0; e.mask = 0; if (buf < e.v) { while (NULL != (key = strsep(&buf, ","))) { - if ('i' == key[0] && '\0' == key[1]) { - icase = REG_ICASE; - continue; - } i = 0; while (types[i].mask && strcmp(types[i].name, key)) @@ -498,9 +670,11 @@ exprcomp(char *buf) if (0 == e.mask) e.mask = TYPE_Nm | TYPE_Nd; - if (e.regex && - regcomp(&e.re, e.v, REG_EXTENDED | REG_NOSUB | icase)) - return(NULL); + if (e.regex) { + i = REG_EXTENDED | REG_NOSUB | cs ? 0 : REG_ICASE; + if (regcomp(&e.re, e.v, i)) + return(NULL); + } e.v = mandoc_strdup(e.v); @@ -512,26 +686,96 @@ exprcomp(char *buf) void exprfree(struct expr *p) { + struct expr *pp; + + while (NULL != p) { + if (p->subexpr) + exprfree(p->subexpr); + if (p->regex) + regfree(&p->re); + free(p->v); + pp = p->next; + free(p); + p = pp; + } +} - if (NULL == p) - return; +static int +exprmark(const struct expr *p, const char *cp, int mask, int *ms) +{ - if (p->regex) - regfree(&p->re); + for ( ; p; p = p->next) { + if (p->subexpr) { + if (exprmark(p->subexpr, cp, mask, ms)) + return(1); + continue; + } else if ( ! (mask & p->mask)) + continue; - free(p->v); - free(p); + if (p->regex) { + if (regexec(&p->re, cp, 0, NULL, 0)) + continue; + } else if (p->cs) { + if (NULL == strstr(cp, p->v)) + continue; + } else { + if (NULL == strcasestr(cp, p->v)) + continue; + } + + if (NULL == ms) + return(1); + else + ms[p->index] = 1; + } + + return(0); } static int -exprexec(const struct expr *p, char *cp, int mask) +expreval(const struct expr *p, int *ms) { + int match; - if ( ! (mask & p->mask)) - return(0); + /* + * AND has precedence over OR. Analysis is left-right, though + * it doesn't matter because there are no side-effects. + * Thus, step through pairwise ANDs and accumulate their Boolean + * evaluation. If we encounter a single true AND collection or + * standalone term, the whole expression is true (by definition + * of OR). + */ - if (p->regex) - return(0 == regexec(&p->re, cp, 0, NULL, 0)); - else - return(NULL != strcasestr(cp, p->v)); + for (match = 0; p && ! match; p = p->next) { + /* Evaluate a subexpression, if applicable. */ + if (p->subexpr && ! ms[p->index]) + ms[p->index] = expreval(p->subexpr, ms); + + match = ms[p->index]; + for ( ; p->next && p->next->and; p = p->next) { + /* Evaluate a subexpression, if applicable. */ + if (p->next->subexpr && ! ms[p->next->index]) + ms[p->next->index] = + expreval(p->next->subexpr, ms); + match = match && ms[p->next->index]; + } + } + + return(match); +} + +/* + * First, update the array of terms for which this expression evaluates + * to true. + * Second, logically evaluate all terms over the updated array of truth + * values. + * If this evaluates to true, mark the expression as satisfied. + */ +static void +exprexec(const struct expr *p, const char *cp, int mask, struct rec *r) +{ + + assert(0 == r->matched); + exprmark(p, cp, mask, r->matches); + r->matched = expreval(p, r->matches); }